Ken and Ian had the same number of cards. Ken gave away
34 of his cards while Ian gave away
35 of his cards. Given that Ken gave away 12 cards more than Ian, how many cards did Ken have at first?
| |
Ken's cards |
Ian's cards |
| Before |
4x5 =
20 u |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 3x4 =
- 12 u |
| After |
1x5 =
5 u |
2x4 =
8 u |
The number of cards that Ken and Ian each had at first is the same. Make the number of cards that Ken and Ian each had at first the same. LCM of 4 and 5 is 20.
Number of cards that Ken gave away more than Ian
= 15 u - 12 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of cards that Ken had at first
= 20 u
= 20 x 4
= 80
Answer(s): 80
