There are some croissants in the jar. On Thursday, Paul ate
37 of the croissants. He later bought 20 croissants and added into the jar. On Friday, Paul ate 46 croissants. He was hungry and ate another 38 croissants. There were no croissants left. How many croissants were there in the jar at first?
|
Croissants |
Before |
7 u |
Change 1 |
- 3 u |
Change 2 |
+ 20 |
Change 3 |
- 46 |
Change 4 |
- 38 |
After |
0 |
Fraction of the croissants left after Paul first ate on Thursday
= 1 -
37=
47Number of croissants left after Paul first ate on Thursday = 4 u
4 u = 38 + 46 - 20
4 u = 64
1 u = 64 ÷ 4 = 16
Number of croissants at first
= 7 u
= 7 x 16
= 112
Answer(s): 112