There are some croissants in the jar. On Thursday, Fred ate
47 of the croissants. He later bought 23 croissants and added into the jar. On Friday, Fred ate 37 croissants. He was hungry and ate another 34 croissants. There were no croissants left. How many croissants were there in the jar at first?
|
Croissants |
Before |
7 u |
Change 1 |
- 4 u |
Change 2 |
+ 23 |
Change 3 |
- 37 |
Change 4 |
- 34 |
After |
0 |
Fraction of the croissants left after Fred first ate on Thursday
= 1 -
47=
37Number of croissants left after Fred first ate on Thursday = 3 u
3 u = 34 + 37 - 23
3 u = 48
1 u = 48 ÷ 3 = 16
Number of croissants at first
= 7 u
= 7 x 16
= 112
Answer(s): 112