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Question

Unit conversion, Time, W Addition & subtraction, Mixed numbers

P4.ME.JM.17100366-A1

4¹₁₀ h 33 s - 2 h 41 min = s

2 m

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4¹₁₀ h 33 s - 2 h 41 min = s
1 min = 60 s
1 h = 60 min

¹₁₀ h = ¹₁₀ x 60 = 6 min

4¹₁₀ h 33 s - 2 h 41 min
= 4 h 6 min 33 s - 2 h 41 min
= 2 h 6 min 33 s - 41 min
= 1 h 66 min 33 s - 41 min
= 1 h 25 min 33 s

1 h 25 min 33 s
= (1 x 60 + 25) min + 33 s
= (60 + 25) min + 33 s
= 85 min + 33 s
= 85 x 60 + 33
= 5100 + 33
= 5133 s

Answer(s): 5133

2 m

4¹₁₀ h 33 s - 2 h 41 min = s

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Ischool Pte Ltd

Date:03 Jun 2024

Topic: MEASUREMENT

Question Code: P4.ME.JM.17100366

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4¹₁₀ h 33 s - 2 h 41 min = s

(2 m)

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Ischool Pte Ltd

Date: 03 Jun 2024

Topic: MEASUREMENT

Question Code: P4.ME.JM.17100366

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4¹₁₀ h 33 s - 2 h 41 min = s

(2 m)

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Primary 4 MEASUREMENT P4.ME.JM.17100366

03 Jun 2024, 03:49 PM

4¹₁₀ h 33 s - 2 h 41 min = s

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Date:03 Jun 2024

Topic:MEASUREMENT

Question Number:P4.ME.JM.17100366-A1

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Date:03 Jun 2024

Topic: MEASUREMENT

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Ischool Pte Ltd

Date:03 Jun 2024

Topic: MEASUREMENT

Question Code: P4.ME.JM.17100366

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Ischool Pte Ltd

Date: 03 Jun 2024

Topic: MEASUREMENT

Question Code: P4.ME.JM.17100366

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