David drank
23 of the distilled water in his distilled water bottle. He accidentally spilled
25 of the remaining distilled water. As a result, he had 510 mℓ of distilled water left in his distilled water bottle. How much distilled water did David have at first? Give your answer in mℓ.
| Drank |
Remaining distilled water |
Total |
| 2x5 |
1x5 |
3x5 |
| |
Spilled |
Left |
|
| |
2x1 |
3x1 |
|
| 10 u |
2 u |
3 u |
15 u |
Fraction of remaining distilled water left after David spilled some
= 1 -
23=
13The volume of the remaining distilled water is the combined repeated identity. Make the volume of remaining distilled water the same. LCM of 1 and 5 is 5.
Volume of water left = 3 u
3 u = 510
1 u = 510 ÷ 3 = 170
Total volume of water that David had at first
= 15 u
= 15 x 170
= 2550 mℓ
Answer(s): 2550 mℓ
