Julian drank
56 of the water in his water bottle. He accidentally spilled
45 of the remaining water. As a result, he had 90 mℓ of water left in his water bottle. How much water did Julian have at first? Give your answer in mℓ.
| Drank |
Remaining water |
Total |
| 5x5 |
1x5 |
6x5 |
| |
Spilled |
Left |
|
| |
4x1 |
1x1 |
|
| 25 u |
4 u |
1 u |
30 u |
Fraction of remaining water left after Julian spilled some
= 1 -
56=
16The volume of the remaining water is the combined repeated identity. Make the volume of remaining water the same. LCM of 1 and 5 is 5.
Volume of water left = 1 u
1 u = 90
Total volume of water that Julian had at first
= 30 u
= 30 x 90
= 2700 mℓ
Answer(s): 2700 mℓ
