Ken drank
23 of the water in his water bottle. He accidentally spilled
12 of the remaining water. As a result, he had 80 mℓ of water left in his water bottle. How much water did Ken have at first? Give your answer in mℓ.
| Drank |
Remaining water |
Total |
| 2x2 |
1x2 |
3x2 |
| |
Spilled |
Left |
|
| |
1x1 |
1x1 |
|
| 4 u |
1 u |
1 u |
6 u |
Fraction of remaining water left after Ken spilled some
= 1 -
23=
13The volume of the remaining water is the combined repeated identity. Make the volume of remaining water the same. LCM of 1 and 2 is 2.
Volume of water left = 1 u
1 u = 80
Total volume of water that Ken had at first
= 6 u
= 6 x 80
= 480 mℓ
Answer(s): 480 mℓ
