Riordan drank
23 of the juice in his juice bottle. He accidentally spilled
12 of the remaining juice. As a result, he had 160 mℓ of juice left in his juice bottle. How much juice did Riordan have at first? Give your answer in mℓ.
Drank |
Remaining juice |
Total |
2x2 |
1x2 |
3x2 |
|
Spilled |
Left |
|
|
1x1 |
1x1 |
|
4 u |
1 u |
1 u |
6 u |
Fraction of remaining juice left after Riordan spilled some
= 1 -
23=
13The volume of the remaining juice is the combined repeated identity. Make the volume of remaining juice the same. LCM of 1 and 2 is 2.
Volume of water left = 1 u
1 u = 160
Total volume of water that Riordan had at first
= 6 u
= 6 x 160
= 960 mℓ
Answer(s): 960 mℓ