Howard drank
23 of the distilled water in his distilled water bottle. He accidentally spilled
13 of the remaining distilled water. As a result, he had 20 mℓ of distilled water left in his distilled water bottle. How much distilled water did Howard have at first? Give your answer in mℓ.
Drank |
Remaining distilled water |
Total |
2x3 |
1x3 |
3x3 |
|
Spilled |
Left |
|
|
1x1 |
2x1 |
|
6 u |
1 u |
2 u |
9 u |
Fraction of remaining distilled water left after Howard spilled some
= 1 -
23=
13The volume of the remaining distilled water is the combined repeated identity. Make the volume of remaining distilled water the same. LCM of 1 and 3 is 3.
Volume of water left = 2 u
2 u = 20
1 u = 20 ÷ 2 = 10
Total volume of water that Howard had at first
= 9 u
= 9 x 10
= 90 mℓ
Answer(s): 90 mℓ