Lee drank
12 of the water in his water bottle. He accidentally spilled
23 of the remaining water. As a result, he had 100 mℓ of water left in his water bottle. How much water did Lee have at first? Give your answer in mℓ.
| Drank |
Remaining water |
Total |
| 1x3 |
1x3 |
2x3 |
| |
Spilled |
Left |
|
| |
2x1 |
1x1 |
|
| 3 u |
2 u |
1 u |
6 u |
Fraction of remaining water left after Lee spilled some
= 1 -
12=
12The volume of the remaining water is the combined repeated identity. Make the volume of remaining water the same. LCM of 1 and 3 is 3.
Volume of water left = 1 u
1 u = 100
Total volume of water that Lee had at first
= 6 u
= 6 x 100
= 600 mℓ
Answer(s): 600 mℓ
