A pail contained 4.7 ℓ more water than a pot. After some water was poured from the pail to the pot, both the pail and the pot had 5 ℓ of water each. How much water was there in the pot at first?
| |
Pail |
Pot |
Total |
| Before |
1 u + 4.7 |
1 u |
10 |
| Change |
- ? |
+ ? |
|
| After |
5 |
5 |
10 |
Volume of water in the pot = 1 u
Volume of water in the pail = 1 u + 4.7
Total volume of water
= 1 u + 1 u + 4.7
= 2 u + 4.7
Total volume of water
= 2 x 5
= 10 ℓ
When water is poured from the pail to the pot, the total volume remains unchanged.
2 u + 4.7 = 10
2 u = 10 - 4.7
2 u = 5.3
1 u = 5.3 ÷ 2 = 2.65
Volume of water in the pot at first = 2.65 ℓ
Answer(s): 2.65 ℓ
