A pot contained 2.1 ℓ more water than a can. After some water was poured from the pot to the can, both the pot and the can had 6 ℓ of water each. How much water was there in the can at first?
| |
Pot |
Can |
Total |
| Before |
1 u + 2.1 |
1 u |
12 |
| Change |
- ? |
+ ? |
|
| After |
6 |
6 |
12 |
Volume of water in the can = 1 u
Volume of water in the pot = 1 u + 2.1
Total volume of water
= 1 u + 1 u + 2.1
= 2 u + 2.1
Total volume of water
= 2 x 6
= 12 ℓ
When water is poured from the pot to the can, the total volume remains unchanged.
2 u + 2.1 = 12
2 u = 12 - 2.1
2 u = 9.9
1 u = 9.9 ÷ 2 = 4.95
Volume of water in the can at first = 4.95 ℓ
Answer(s): 4.95 ℓ
