A pail contained 3.1 ℓ more water than a can. After some water was poured from the pail to the can, both the pail and the can had 5 ℓ of water each. How much water was there in the can at first?
|
Pail |
Can |
Total |
Before |
1 u + 3.1 |
1 u |
10 |
Change |
- ? |
+ ? |
|
After |
5 |
5 |
10 |
Volume of water in the can = 1 u
Volume of water in the pail = 1 u + 3.1
Total volume of water
= 1 u + 1 u + 3.1
= 2 u + 3.1
Total volume of water
= 2 x 5
= 10 ℓ
When water is poured from the pail to the can, the total volume remains unchanged.
2 u + 3.1 = 10
2 u = 10 - 3.1
2 u = 6.9
1 u = 6.9 ÷ 2 = 3.45
Volume of water in the can at first = 3.45 ℓ
Answer(s): 3.45 ℓ