A pail contained 3.9 ℓ more water than a watering can. After some water was poured from the pail to the watering can, both the pail and the watering can had 7 ℓ of water each. How much water was there in the watering can at first?
| |
Pail |
Watering Can |
Total |
| Before |
1 u + 3.9 |
1 u |
14 |
| Change |
- ? |
+ ? |
|
| After |
7 |
7 |
14 |
Volume of water in the watering can = 1 u
Volume of water in the pail = 1 u + 3.9
Total volume of water
= 1 u + 1 u + 3.9
= 2 u + 3.9
Total volume of water
= 2 x 7
= 14 ℓ
When water is poured from the pail to the watering can, the total volume remains unchanged.
2 u + 3.9 = 14
2 u = 14 - 3.9
2 u = 10.1
1 u = 10.1 ÷ 2 = 5.05
Volume of water in the watering can at first = 5.05 ℓ
Answer(s): 5.05 ℓ
