A pot contained 4.7 ℓ more water than a watering can. After some water was poured from the pot to the watering can, both the pot and the watering can had 6 ℓ of water each. How much water was there in the watering can at first?
| |
Pot |
Watering Can |
Total |
| Before |
1 u + 4.7 |
1 u |
12 |
| Change |
- ? |
+ ? |
|
| After |
6 |
6 |
12 |
Volume of water in the watering can = 1 u
Volume of water in the pot = 1 u + 4.7
Total volume of water
= 1 u + 1 u + 4.7
= 2 u + 4.7
Total volume of water
= 2 x 6
= 12 ℓ
When water is poured from the pot to the watering can, the total volume remains unchanged.
2 u + 4.7 = 12
2 u = 12 - 4.7
2 u = 7.3
1 u = 7.3 ÷ 2 = 3.65
Volume of water in the watering can at first = 3.65 ℓ
Answer(s): 3.65 ℓ
