A pot contained 3.7 ℓ more water than a pail. After some water was poured from the pot to the pail, both the pot and the pail had 6 ℓ of water each. How much water was there in the pail at first?
|
Pot |
Pail |
Total |
Before |
1 u + 3.7 |
1 u |
12 |
Change |
- ? |
+ ? |
|
After |
6 |
6 |
12 |
Volume of water in the pail = 1 u
Volume of water in the pot = 1 u + 3.7
Total volume of water
= 1 u + 1 u + 3.7
= 2 u + 3.7
Total volume of water
= 2 x 6
= 12 ℓ
When water is poured from the pot to the pail, the total volume remains unchanged.
2 u + 3.7 = 12
2 u = 12 - 3.7
2 u = 8.3
1 u = 8.3 ÷ 2 = 4.15
Volume of water in the pail at first = 4.15 ℓ
Answer(s): 4.15 ℓ