A pot contained 3.9 ℓ more water than a watering can. After some water was poured from the pot to the watering can, both the pot and the watering can had 4 ℓ of water each. How much water was there in the watering can at first?
|
Pot |
Watering Can |
Total |
Before |
1 u + 3.9 |
1 u |
8 |
Change |
- ? |
+ ? |
|
After |
4 |
4 |
8 |
Volume of water in the watering can = 1 u
Volume of water in the pot = 1 u + 3.9
Total volume of water
= 1 u + 1 u + 3.9
= 2 u + 3.9
Total volume of water
= 2 x 4
= 8 ℓ
When water is poured from the pot to the watering can, the total volume remains unchanged.
2 u + 3.9 = 8
2 u = 8 - 3.9
2 u = 4.1
1 u = 4.1 ÷ 2 = 2.05
Volume of water in the watering can at first = 2.05 ℓ
Answer(s): 2.05 ℓ