A pail contained 4.7 ℓ more water than a can. After some water was poured from the pail to the can, both the pail and the can had 7 ℓ of water each. How much water was there in the can at first?
|
Pail |
Can |
Total |
Before |
1 u + 4.7 |
1 u |
14 |
Change |
- ? |
+ ? |
|
After |
7 |
7 |
14 |
Volume of water in the can = 1 u
Volume of water in the pail = 1 u + 4.7
Total volume of water
= 1 u + 1 u + 4.7
= 2 u + 4.7
Total volume of water
= 2 x 7
= 14 ℓ
When water is poured from the pail to the can, the total volume remains unchanged.
2 u + 4.7 = 14
2 u = 14 - 4.7
2 u = 9.3
1 u = 9.3 ÷ 2 = 4.65
Volume of water in the can at first = 4.65 ℓ
Answer(s): 4.65 ℓ