A pail contained 3.9 ℓ more water than a can. After some water was poured from the pail to the can, both the pail and the can had 6 ℓ of water each. How much water was there in the can at first?
| |
Pail |
Can |
Total |
| Before |
1 u + 3.9 |
1 u |
12 |
| Change |
- ? |
+ ? |
|
| After |
6 |
6 |
12 |
Volume of water in the can = 1 u
Volume of water in the pail = 1 u + 3.9
Total volume of water
= 1 u + 1 u + 3.9
= 2 u + 3.9
Total volume of water
= 2 x 6
= 12 ℓ
When water is poured from the pail to the can, the total volume remains unchanged.
2 u + 3.9 = 12
2 u = 12 - 3.9
2 u = 8.1
1 u = 8.1 ÷ 2 = 4.05
Volume of water in the can at first = 4.05 ℓ
Answer(s): 4.05 ℓ
