Container Z has thrice as much water as Container Y. If Ahmad adds 0.6 ℓ of water to Container Z and 2.5 ℓ of water to Container Y, both containers will have the same volume of water. Find the volume of water in Container Z at first.
| |
Y |
Z |
| Before |
1 u |
3 u |
| Change |
+ 2.5 |
+ 0.6 |
| After |
1 u + 2.5 |
3 u + 0.6 |
Both containers have the same volume of water in the end.
3 u + 0.6 = 1 u + 2.5
3 u - 1 u = 2.5 - 0.6
2 u = 1.9
1 u = 1.9 ÷ 2 = 0.95
Volume of water in Container Z at first
= 3 u
= 3 x 0.95
= 2.85 ℓ
Answer(s): 2.85 ℓ
