Container S has thrice as much water as Container R. If Ian adds 0.7 ℓ of water to Container S and 2.4 ℓ of water to Container R, both containers will have the same volume of water. Find the volume of water in Container S at first.
|
R |
S |
Before |
1 u |
3 u |
Change |
+ 2.4 |
+ 0.7 |
After |
1 u + 2.4 |
3 u + 0.7 |
Both containers have the same volume of water in the end.
3 u + 0.7 = 1 u + 2.4
3 u - 1 u = 2.4 - 0.7
2 u = 1.7
1 u = 1.7 ÷ 2 = 0.85
Volume of water in Container S at first
= 3 u
= 3 x 0.85
= 2.55 ℓ
Answer(s): 2.55 ℓ