Tank B has thrice as much water as Tank A. If Tom adds 1.1 ℓ of water to Tank B and 2.8 ℓ of water to Tank A, both tanks will have the same volume of water. Find the volume of water in Tank B at first.
|
A |
B |
Before |
1 u |
3 u |
Change |
+ 2.8 |
+ 1.1 |
After |
1 u + 2.8 |
3 u + 1.1 |
Both tanks have the same volume of water in the end.
3 u + 1.1 = 1 u + 2.8
3 u - 1 u = 2.8 - 1.1
2 u = 1.7
1 u = 1.7 ÷ 2 = 0.85
Volume of water in Tank B at first
= 3 u
= 3 x 0.85
= 2.55 ℓ
Answer(s): 2.55 ℓ