Tank G has thrice as much water as Tank F. If Lee adds 1.1 ℓ of water to Tank G and 2.4 ℓ of water to Tank F, both tanks will have the same volume of water. Find the volume of water in Tank G at first.
| |
F |
G |
| Before |
1 u |
3 u |
| Change |
+ 2.4 |
+ 1.1 |
| After |
1 u + 2.4 |
3 u + 1.1 |
Both tanks have the same volume of water in the end.
3 u + 1.1 = 1 u + 2.4
3 u - 1 u = 2.4 - 1.1
2 u = 1.3
1 u = 1.3 ÷ 2 = 0.65
Volume of water in Tank G at first
= 3 u
= 3 x 0.65
= 1.95 ℓ
Answer(s): 1.95 ℓ
