Container N has thrice as much water as Container M. If Peter adds 1.1 ℓ of water to Container N and 2.6 ℓ of water to Container M, both containers will have the same volume of water. Find the volume of water in Container N at first.
| |
M |
N |
| Before |
1 u |
3 u |
| Change |
+ 2.6 |
+ 1.1 |
| After |
1 u + 2.6 |
3 u + 1.1 |
Both containers have the same volume of water in the end.
3 u + 1.1 = 1 u + 2.6
3 u - 1 u = 2.6 - 1.1
2 u = 1.5
1 u = 1.5 ÷ 2 = 0.75
Volume of water in Container N at first
= 3 u
= 3 x 0.75
= 2.25 ℓ
Answer(s): 2.25 ℓ
