Container M has thrice as much water as Container L. If Mark adds 0.9 ℓ of water to Container M and 2.2 ℓ of water to Container L, both containers will have the same volume of water. Find the volume of water in Container M at first.
| |
L |
M |
| Before |
1 u |
3 u |
| Change |
+ 2.2 |
+ 0.9 |
| After |
1 u + 2.2 |
3 u + 0.9 |
Both containers have the same volume of water in the end.
3 u + 0.9 = 1 u + 2.2
3 u - 1 u = 2.2 - 0.9
2 u = 1.3
1 u = 1.3 ÷ 2 = 0.65
Volume of water in Container M at first
= 3 u
= 3 x 0.65
= 1.95 ℓ
Answer(s): 1.95 ℓ
