Tank Y has thrice as much water as Tank X. If Luke adds 0.3 ℓ of water to Tank Y and 2.2 ℓ of water to Tank X, both tanks will have the same volume of water. Find the volume of water in Tank Y at first.
| |
X |
Y |
| Before |
1 u |
3 u |
| Change |
+ 2.2 |
+ 0.3 |
| After |
1 u + 2.2 |
3 u + 0.3 |
Both tanks have the same volume of water in the end.
3 u + 0.3 = 1 u + 2.2
3 u - 1 u = 2.2 - 0.3
2 u = 1.9
1 u = 1.9 ÷ 2 = 0.95
Volume of water in Tank Y at first
= 3 u
= 3 x 0.95
= 2.85 ℓ
Answer(s): 2.85 ℓ
