Tank H has thrice as much water as Tank G. If Fred adds 0.4 ℓ of water to Tank H and 2.3 ℓ of water to Tank G, both tanks will have the same volume of water. Find the volume of water in Tank H at first.
| |
G |
H |
| Before |
1 u |
3 u |
| Change |
+ 2.3 |
+ 0.4 |
| After |
1 u + 2.3 |
3 u + 0.4 |
Both tanks have the same volume of water in the end.
3 u + 0.4 = 1 u + 2.3
3 u - 1 u = 2.3 - 0.4
2 u = 1.9
1 u = 1.9 ÷ 2 = 0.95
Volume of water in Tank H at first
= 3 u
= 3 x 0.95
= 2.85 ℓ
Answer(s): 2.85 ℓ
