Container Y has thrice as much water as Container X. If Perry adds 0.8 ℓ of water to Container Y and 2.7 ℓ of water to Container X, both containers will have the same volume of water. Find the volume of water in Container Y at first.
| |
X |
Y |
| Before |
1 u |
3 u |
| Change |
+ 2.7 |
+ 0.8 |
| After |
1 u + 2.7 |
3 u + 0.8 |
Both containers have the same volume of water in the end.
3 u + 0.8 = 1 u + 2.7
3 u - 1 u = 2.7 - 0.8
2 u = 1.9
1 u = 1.9 ÷ 2 = 0.95
Volume of water in Container Y at first
= 3 u
= 3 x 0.95
= 2.85 ℓ
Answer(s): 2.85 ℓ
