Container G has thrice as much water as Container F. If Albert adds 0.8 ℓ of water to Container G and 2.9 ℓ of water to Container F, both containers will have the same volume of water. Find the volume of water in Container G at first.
| |
F |
G |
| Before |
1 u |
3 u |
| Change |
+ 2.9 |
+ 0.8 |
| After |
1 u + 2.9 |
3 u + 0.8 |
Both containers have the same volume of water in the end.
3 u + 0.8 = 1 u + 2.9
3 u - 1 u = 2.9 - 0.8
2 u = 2.1
1 u = 2.1 ÷ 2 = 1.05
Volume of water in Container G at first
= 3 u
= 3 x 1.05
= 3.15 ℓ
Answer(s): 3.15 ℓ
