Tank S has thrice as much water as Tank R. If Tim adds 0.9 ℓ of water to Tank S and 2.6 ℓ of water to Tank R, both tanks will have the same volume of water. Find the volume of water in Tank S at first.
| |
R |
S |
| Before |
1 u |
3 u |
| Change |
+ 2.6 |
+ 0.9 |
| After |
1 u + 2.6 |
3 u + 0.9 |
Both tanks have the same volume of water in the end.
3 u + 0.9 = 1 u + 2.6
3 u - 1 u = 2.6 - 0.9
2 u = 1.7
1 u = 1.7 ÷ 2 = 0.85
Volume of water in Tank S at first
= 3 u
= 3 x 0.85
= 2.55 ℓ
Answer(s): 2.55 ℓ
