Betty bought 8 shortbreads more than wafers. Each shortbread cost $1.80 while each wafer cost $2.30. Given that she spent $26.70 in total, how many wafers did Betty buy?
| |
Wafers |
Shortbreads |
Total |
| Number |
1 u |
1 u + 8 |
|
| Value |
$2.30 |
$1.80 |
|
| Total value |
2.3 u |
1.8 u + 14.4 |
1.8 u + 14.4 |
Amount that Betty paid for the wafers
= 1 u x 2.30
= 2.3 u
Amount that Betty paid for shortbreads
= 1.8 x (1 u + 8)
= 1.8 u + 14.4
Total amount that Betty paid
= 2.3 u + 1.8 u + 14.4
= 4.1 u + 14.4
4.1 u + 14.4 = 26.7
4.1 u = 26.7 - 14.4
4.1 u = 12.3
1 u = 12.3 ÷ 4.1 = 3
Number of wafers that Betty bought
= 1 u
= 3
Answer(s): 3
