Eva bought 8 wafers more than shortbreads. Each wafer cost $1.20 while each shortbread cost $1.70. Given that she spent $29.90 in total, how many shortbreads did Eva buy?
| |
Shortbreads |
Wafers |
Total |
| Number |
1 u |
1 u + 8 |
|
| Value |
$1.70 |
$1.20 |
|
| Total value |
1.7 u |
1.2 u + 9.6 |
1.2 u + 9.6 |
Amount that Eva paid for the shortbreads
= 1 u x 1.70
= 1.7 u
Amount that Eva paid for wafers
= 1.2 x (1 u + 8)
= 1.2 u + 9.6
Total amount that Eva paid
= 1.7 u + 1.2 u + 9.6
= 2.9 u + 9.6
2.9 u + 9.6 = 29.9
2.9 u = 29.9 - 9.6
2.9 u = 20.3
1 u = 20.3 ÷ 2.9 = 7
Number of shortbreads that Eva bought
= 1 u
= 7
Answer(s): 7
