Sam bought a total of 14 sweets and caramel apples. Each sweet cost 40¢. Each caramel apple cost 90¢. He paid a total of $9.60. How many caramel apples did he buy?
Number of
sweets |
Amount paid
for the sweets |
Number of
caramel apples |
Amount paid
for the sweets |
Total paid |
| 14 |
14 x 40
= 560¢ |
0 |
0 |
560¢ |
| 13 |
13 x 40
= 520¢ |
1 |
1 x 90
= 90¢ |
610¢ |
| 6 |
6 x 40
= 240¢ |
8 |
8 x 90
= 720¢ |
960¢ |
$1 = 100¢
$9.60 = 960¢
Amount paid if all were sweets
= 14 x 40
= 560¢
Big difference between the amount paid for the sweets and the caramel apples
= 960 - 560
= 400¢
Small difference between the amount paid for the one sweet and one caramel apple
= 90 - 40
= 50¢
Number of caramel apples
= 400 ÷ 50
= 8
Answer(s): 8
