Pierre bought a total of 15 sweets and caramel apples. Each sweet cost 40¢. Each caramel apple cost 70¢. He paid a total of $8.70. How many caramel apples did he buy?
Number of
sweets |
Amount paid
for the sweets |
Number of
caramel apples |
Amount paid
for the sweets |
Total paid |
| 15 |
15 x 40
= 600¢ |
0 |
0 |
600¢ |
| 14 |
14 x 40
= 560¢ |
1 |
1 x 70
= 70¢ |
630¢ |
| 6 |
6 x 40
= 240¢ |
9 |
9 x 70
= 630¢ |
870¢ |
$1 = 100¢
$8.70 = 870¢
Amount paid if all were sweets
= 15 x 40
= 600¢
Big difference between the amount paid for the sweets and the caramel apples
= 870 - 600
= 270¢
Small difference between the amount paid for the one sweet and one caramel apple
= 70 - 40
= 30¢
Number of caramel apples
= 270 ÷ 30
= 9
Answer(s): 9
