Albert bought a total of 11 caramel apples and chocolate bars. Each caramel apple cost 50¢. Each chocolate bar cost 60¢. He paid a total of $5.90. How many chocolate bars did he buy?
Number of
caramel apples |
Amount paid
for the caramel apples |
Number of
chocolate bars |
Amount paid
for the caramel apples |
Total paid |
| 11 |
11 x 50
= 550¢ |
0 |
0 |
550¢ |
| 10 |
10 x 50
= 500¢ |
1 |
1 x 60
= 60¢ |
560¢ |
| 7 |
7 x 50
= 350¢ |
4 |
4 x 60
= 240¢ |
590¢ |
$1 = 100¢
$5.90 = 590¢
Amount paid if all were caramel apples
= 11 x 50
= 550¢
Big difference between the amount paid for the caramel apples and the chocolate bars
= 590 - 550
= 40¢
Small difference between the amount paid for the one caramel apple and one chocolate bar
= 60 - 50
= 10¢
Number of chocolate bars
= 40 ÷ 10
= 4
Answer(s): 4
