Warren bought a total of 20 caramel apples and chocolate bars. Each caramel apple cost 40¢. Each chocolate bar cost 50¢. He paid a total of $8.40. How many chocolate bars did he buy?
Number of
caramel apples |
Amount paid
for the caramel apples |
Number of
chocolate bars |
Amount paid
for the caramel apples |
Total paid |
| 20 |
20 x 40
= 800¢ |
0 |
0 |
800¢ |
| 19 |
19 x 40
= 760¢ |
1 |
1 x 50
= 50¢ |
810¢ |
| 16 |
16 x 40
= 640¢ |
4 |
4 x 50
= 200¢ |
840¢ |
$1 = 100¢
$8.40 = 840¢
Amount paid if all were caramel apples
= 20 x 40
= 800¢
Big difference between the amount paid for the caramel apples and the chocolate bars
= 840 - 800
= 40¢
Small difference between the amount paid for the one caramel apple and one chocolate bar
= 50 - 40
= 10¢
Number of chocolate bars
= 40 ÷ 10
= 4
Answer(s): 4
