Elijah bought a total of 19 candy canes and caramel apples. Each candy cane cost 40¢. Each caramel apple cost 50¢. He paid a total of $8.70. How many caramel apples did he buy?
Number of candy canes |
Amount paid for the candy canes |
Number of caramel apples |
Amount paid for the candy canes |
Total paid |
19 |
19 x 40 = 760¢ |
0 |
0 |
760¢ |
18 |
18 x 40 = 720¢ |
1 |
1 x 50 = 50¢ |
770¢ |
8 |
8 x 40 = 320¢ |
11 |
11 x 50 = 550¢ |
870¢ |
$1 = 100¢
$8.70 = 870¢
Amount paid if all were candy canes
= 19 x 40
= 760¢
Big difference between the amount paid for the candy canes and the caramel apples
= 870 - 760
= 110¢
Small difference between the amount paid for the one candy cane and one caramel apple
= 50 - 40
= 10¢
Number of caramel apples
= 110 ÷ 10
= 11
Answer(s): 11