There were a total of forty-six 10-cent coins and 50-cent coins in a bag. Given that the total amount of money in the bag was $210. How many 10-cent coins were there in the bag?
Number of 50-cent coins |
Value of 50-cent coins |
Number of 10-cent coins |
Value of 10-cent coins |
Total value |
46
|
46 x 50 = 2300¢ |
0
|
0
|
2300¢
|
45
|
45 x 50 = 2250¢ |
1
|
1 x 10 = 10¢ |
2260¢
|
41
|
41 x 50 = 2050¢ |
5
|
5 x 10 = 50¢ |
2100¢ |
$1 = 100¢
$210 = 2100¢
Amount in the bag if all are 50-cent coins
= 46 x 50
= 2300¢
Big difference between the value of 50-cent coins and 10-cent coins
= 2300 - 2100
= 200¢
Small difference between the value of one 50-cent coin and one 10-cent coin
= 50 - 10
= 40¢
Number of 10-cent coins
= 200 ÷ 40
= 5
Answer(s): 5