There were a total of forty-three 10-cent coins and 50-cent coins in a bag. Given that the total amount of money in the bag was $14.70. How many 10-cent coins were there in the bag?
Number of 50-cent coins |
Value of 50-cent coins |
Number of 10-cent coins |
Value of 10-cent coins |
Total value |
43
|
43 x 50 = 2150¢ |
0
|
0
|
2150¢
|
42
|
42 x 50 = 2100¢ |
1
|
1 x 10 = 10¢ |
2110¢
|
26
|
26 x 50 = 1300¢ |
17
|
17 x 10 = 170¢ |
1470¢ |
$1 = 100¢
$14.70 = 1470¢
Amount in the bag if all are 50-cent coins
= 43 x 50
= 2150¢
Big difference between the value of 50-cent coins and 10-cent coins
= 2150 - 1470
= 680¢
Small difference between the value of one 50-cent coin and one 10-cent coin
= 50 - 10
= 40¢
Number of 10-cent coins
= 680 ÷ 40
= 17
Answer(s): 17