There were a total of forty-five 10-cent coins and 50-cent coins in a bag. Given that the total amount of money in the bag was $18.10. How many 10-cent coins were there in the bag?
Number of 50-cent coins |
Value of 50-cent coins |
Number of 10-cent coins |
Value of 10-cent coins |
Total value |
45
|
45 x 50 = 2250¢ |
0
|
0
|
2250¢
|
44
|
44 x 50 = 2200¢ |
1
|
1 x 10 = 10¢ |
2210¢
|
34
|
34 x 50 = 1700¢ |
11
|
11 x 10 = 110¢ |
1810¢ |
$1 = 100¢
$18.10 = 1810¢
Amount in the bag if all are 50-cent coins
= 45 x 50
= 2250¢
Big difference between the value of 50-cent coins and 10-cent coins
= 2250 - 1810
= 440¢
Small difference between the value of one 50-cent coin and one 10-cent coin
= 50 - 10
= 40¢
Number of 10-cent coins
= 440 ÷ 40
= 11
Answer(s): 11