There were a total of forty-four 20-cent coins and 50-cent coins in a bag. Given that the total amount of money in the bag was $18.10. How many 20-cent coins were there in the bag?
Number of
50-cent coins |
Value of
50-cent coins |
Number of
20-cent coins |
Value of
20-cent coins |
Total
value |
44
|
44 x 50
= 2200¢ |
0
|
0
|
2200¢
|
43
|
43 x 50
= 2150¢ |
1
|
1 x 20
= 20¢ |
2170¢
|
31
|
31 x 50
= 1550¢ |
13
|
13 x 20
= 260¢ |
1810¢ |
$1 = 100¢
$18.10 = 1810¢
Amount in the bag if all are 50-cent coins
= 44 x 50
= 2200¢
Big difference between the value of 50-cent coins and 20-cent coins
= 2200 - 1810
= 390¢
Small difference between the value of one 50-cent coin and one 20-cent coin
= 50 - 20
= 30¢
Number of 20-cent coins
= 390 ÷ 30
= 13
Answer(s): 13
