There were a total of forty-four 10-cent coins and 20-cent coins in a bag. Given that the total amount of money in the bag was $7.20. How many 10-cent coins were there in the bag?
Number of 20-cent coins |
Value of 20-cent coins |
Number of 10-cent coins |
Value of 10-cent coins |
Total value |
44
|
44 x 20 = 880¢ |
0
|
0
|
880¢
|
43
|
43 x 20 = 860¢ |
1
|
1 x 10 = 10¢ |
870¢
|
28
|
28 x 20 = 560¢ |
16
|
16 x 10 = 160¢ |
720¢ |
$1 = 100¢
$7.20 = 720¢
Amount in the bag if all are 20-cent coins
= 44 x 20
= 880¢
Big difference between the value of 20-cent coins and 10-cent coins
= 880 - 720
= 160¢
Small difference between the value of one 20-cent coin and one 10-cent coin
= 20 - 10
= 10¢
Number of 10-cent coins
= 160 ÷ 10
= 16
Answer(s): 16