There were a total of forty-three 10-cent coins and 20-cent coins in a bag. Given that the total amount of money in the bag was $70. How many 10-cent coins were there in the bag?
Number of
20-cent coins |
Value of
20-cent coins |
Number of
10-cent coins |
Value of
10-cent coins |
Total
value |
43
|
43 x 20
= 860¢ |
0
|
0
|
860¢
|
42
|
42 x 20
= 840¢ |
1
|
1 x 10
= 10¢ |
850¢
|
27
|
27 x 20
= 540¢ |
16
|
16 x 10
= 160¢ |
700¢ |
$1 = 100¢
$70 = 700¢
Amount in the bag if all are 20-cent coins
= 43 x 20
= 860¢
Big difference between the value of 20-cent coins and 10-cent coins
= 860 - 700
= 160¢
Small difference between the value of one 20-cent coin and one 10-cent coin
= 20 - 10
= 10¢
Number of 10-cent coins
= 160 ÷ 10
= 16
Answer(s): 16
