There were a total of thirty-two 10-cent coins and 50-cent coins in a bag. Given that the total amount of money in the bag was $9.60. How many 10-cent coins were there in the bag?
Number of 50-cent coins |
Value of 50-cent coins |
Number of 10-cent coins |
Value of 10-cent coins |
Total value |
32
|
32 x 50 = 1600¢ |
0
|
0
|
1600¢
|
31
|
31 x 50 = 1550¢ |
1
|
1 x 10 = 10¢ |
1560¢
|
16
|
16 x 50 = 800¢ |
16
|
16 x 10 = 160¢ |
960¢ |
$1 = 100¢
$9.60 = 960¢
Amount in the bag if all are 50-cent coins
= 32 x 50
= 1600¢
Big difference between the value of 50-cent coins and 10-cent coins
= 1600 - 960
= 640¢
Small difference between the value of one 50-cent coin and one 10-cent coin
= 50 - 10
= 40¢
Number of 10-cent coins
= 640 ÷ 40
= 16
Answer(s): 16