Given that ABCD is a rhombus, calculate
- ∠g
- ∠h
(a)
∠AED = ∠BEF = 107° (Vertically opposite angles)
∠g
= 180° - 107° - 19°
= 54° (Angles sum of triangle)
(b)
∠DCB
= 180° - 19° - 19°
= 142° (Angles sum of triangle)
∠h
= 360° - 107° - 142° - 19°
= 92° (Sum of Angles in a quadrilateral)
Answer(s): (a) 54°; (b) 92°