Given that CDEF is a rhombus, calculate
- ∠k
- ∠l
(a)
∠CGF = ∠DGH = 101° (Vertically opposite angles)
∠k
= 180° - 101° - 16°
= 63° (Angles sum of triangle)
(b)
∠FED
= 180° - 16° - 16°
= 148° (Angles sum of triangle)
∠l
= 360° - 101° - 148° - 16°
= 95° (Sum of Angles in a quadrilateral)
Answer(s): (a) 63°; (b) 95°