Given that ABCD is a rhombus, calculate
- ∠g
- ∠h
(a)
∠AED = ∠BEF = 102° (Vertically opposite angles)
∠g
= 180° - 102° - 15°
= 63° (Angles sum of triangle)
(b)
∠DCB
= 180° - 15° - 15°
= 150° (Angles sum of triangle)
∠h
= 360° - 102° - 150° - 15°
= 93° (Sum of Angles in a quadrilateral)
Answer(s): (a) 63°; (b) 93°