Given that FGHK is a rhombus, calculate
- ∠p
- ∠r
(a)
∠FLK = ∠GLN = 108° (Vertically opposite angles)
∠p
= 180° - 108° - 11°
= 61° (Angles sum of triangle)
(b)
∠KHG
= 180° - 11° - 11°
= 158° (Angles sum of triangle)
∠r
= 360° - 108° - 158° - 11°
= 83° (Sum of Angles in a quadrilateral)
Answer(s): (a) 61°; (b) 83°