Given that CDEF is a rhombus, calculate
- ∠k
- ∠l
(a)
∠CGF = ∠DGH = 100° (Vertically opposite angles)
∠k
= 180° - 100° - 23°
= 57° (Angles sum of triangle)
(b)
∠FED
= 180° - 23° - 23°
= 134° (Angles sum of triangle)
∠l
= 360° - 100° - 134° - 23°
= 103° (Sum of Angles in a quadrilateral)
Answer(s): (a) 57°; (b) 103°