Given that DEFG is a rhombus, calculate
- ∠l
- ∠n
(a)
∠DHG = ∠EHK = 111° (Vertically opposite angles)
∠l
= 180° - 111° - 15°
= 54° (Angles sum of triangle)
(b)
∠GFE
= 180° - 15° - 15°
= 150° (Angles sum of triangle)
∠n
= 360° - 111° - 150° - 15°
= 84° (Sum of Angles in a quadrilateral)
Answer(s): (a) 54°; (b) 84°